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14100202052353 is a prime number
BaseRepresentation
bin1100110100101111010110…
…0010001101101100000001
31211220222002022202121201201
43031023311202031230001
53322004203211133403
645553313212501201
72653464102632014
oct315136542155401
954828068677651
1014100202052353
1145469535156aa
1216b886917a801
137b3849588ba1
1436a64c28737b
15196ba2c4a21d
hexcd2f588db01

14100202052353 has 2 divisors, whose sum is σ = 14100202052354. Its totient is φ = 14100202052352.

The previous prime is 14100202052281. The next prime is 14100202052411. The reversal of 14100202052353 is 35325020200141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11203098492609 + 2897103559744 = 3347103^2 + 1702088^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100202052353 - 29 = 14100202051841 is a prime.

It is not a weakly prime, because it can be changed into another prime (14100202002353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050101026176 + 7050101026177.

It is an arithmetic number, because the mean of its divisors is an integer number (7050101026177).

Almost surely, 214100202052353 is an apocalyptic number.

It is an amenable number.

14100202052353 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100202052353 is an equidigital number, since it uses as much as digits as its factorization.

14100202052353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 28.

Adding to 14100202052353 its reverse (35325020200141), we get a palindrome (49425222252494).

The spelling of 14100202052353 in words is "fourteen trillion, one hundred billion, two hundred two million, fifty-two thousand, three hundred fifty-three".