14100211131 has 4 divisors (see below), whose sum is σ = 18800281512. Its totient is φ = 9400140752.

The previous prime is 14100211129. The next prime is 14100211199. The reversal of 14100211131 is 13111200141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14100211131 - 2¹ = 14100211129 is a prime.

It is a super-2 number, since 2×14100211131² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 14100211131.

It is not an unprimeable number, because it can be changed into a prime (14100211831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350035186 + ... + 2350035191.

It is an arithmetic number, because the mean of its divisors is an integer number (4700070378).

Almost surely, 2^14100211131 is an apocalyptic number.

14100211131 is a deficient number, since it is larger than the sum of its proper divisors (4700070381).

14100211131 is an equidigital number, since it uses as much as digits as its factorization.

14100211131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4700070380.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 14100211131 its reverse (13111200141), we get a palindrome (27211411272).

The spelling of 14100211131 in words is "fourteen billion, one hundred million, two hundred eleven thousand, one hundred thirty-one".