141004121723 has 2 divisors, whose sum is σ = 141004121724. Its totient is φ = 141004121722.

The previous prime is 141004121689. The next prime is 141004121801. The reversal of 141004121723 is 327121400141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141004121723 - 2³⁶ = 72284644987 is a prime.

It is a super-3 number, since 3×141004121723³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141004121692 and 141004121701.

It is not a weakly prime, because it can be changed into another prime (141004120723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70502060861 + 70502060862.

It is an arithmetic number, because the mean of its divisors is an integer number (70502060862).

Almost surely, 2^141004121723 is an apocalyptic number.

141004121723 is a deficient number, since it is larger than the sum of its proper divisors (1).

141004121723 is an equidigital number, since it uses as much as digits as its factorization.

141004121723 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 141004121723 its reverse (327121400141), we get a palindrome (468125521864).

The spelling of 141004121723 in words is "one hundred forty-one billion, four million, one hundred twenty-one thousand, seven hundred twenty-three".