Base | Representation |
---|---|
bin | 11010010000111011… |
… | …00111110011010001 |
3 | 1100101200211001101011 |
4 | 31020131213303101 |
5 | 212334230023031 |
6 | 10251105210521 |
7 | 1006266230443 |
oct | 151035476321 |
9 | 40350731334 |
10 | 14100626641 |
11 | 5a86488552 |
12 | 2896330a41 |
13 | 143941197a |
14 | 97a9cc493 |
15 | 577dad6b1 |
hex | 348767cd1 |
14100626641 has 2 divisors, whose sum is σ = 14100626642. Its totient is φ = 14100626640.
The previous prime is 14100626633. The next prime is 14100626647. The reversal of 14100626641 is 14662600141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11580988225 + 2519638416 = 107615^2 + 50196^2 .
It is a cyclic number.
It is not a de Polignac number, because 14100626641 - 23 = 14100626633 is a prime.
It is not a weakly prime, because it can be changed into another prime (14100626647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050313320 + 7050313321.
It is an arithmetic number, because the mean of its divisors is an integer number (7050313321).
Almost surely, 214100626641 is an apocalyptic number.
It is an amenable number.
14100626641 is a deficient number, since it is larger than the sum of its proper divisors (1).
14100626641 is an equidigital number, since it uses as much as digits as its factorization.
14100626641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 31.
The spelling of 14100626641 in words is "fourteen billion, one hundred million, six hundred twenty-six thousand, six hundred forty-one".
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