141010113 has 4 divisors (see below), whose sum is σ = 188013488. Its totient is φ = 94006740.

The previous prime is 141010109. The next prime is 141010187. The reversal of 141010113 is 311010141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 141010113 - 2² = 141010109 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141010313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23501683 + ... + 23501688.

It is an arithmetic number, because the mean of its divisors is an integer number (47003372).

Almost surely, 2^141010113 is an apocalyptic number.

It is an amenable number.

141010113 is a deficient number, since it is larger than the sum of its proper divisors (47003375).

141010113 is an equidigital number, since it uses as much as digits as its factorization.

141010113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47003374.

The product of its (nonzero) digits is 12, while the sum is 12.

The square root of 141010113 is about 11874.7679135215. The cubic root of 141010113 is about 520.4952296410.

Adding to 141010113 its reverse (311010141), we get a palindrome (452020254).

The spelling of 141010113 in words is "one hundred forty-one million, ten thousand, one hundred thirteen".