1410101412121 has 4 divisors (see below), whose sum is σ = 1410110201700. Its totient is φ = 1410092622544.

The previous prime is 1410101412061. The next prime is 1410101412131. The reversal of 1410101412121 is 1212141010141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1104624122121 + 305477290000 = 1051011^2 + 552700^2 .

It is a cyclic number.

It is not a de Polignac number, because 1410101412121 - 2²³ = 1410093023513 is a prime.

It is an alternating number because its digits alternate between odd and even.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1410101412131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4149586 + ... + 4476523.

It is an arithmetic number, because the mean of its divisors is an integer number (352527550425).

Almost surely, 2^{1410101412121} is an apocalyptic number.

It is an amenable number.

1410101412121 is a deficient number, since it is larger than the sum of its proper divisors (8789579).

1410101412121 is an equidigital number, since it uses as much as digits as its factorization.

1410101412121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8789578.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 1410101412121 its reverse (1212141010141), we get a palindrome (2622242422262).

The spelling of 1410101412121 in words is "one trillion, four hundred ten billion, one hundred one million, four hundred twelve thousand, one hundred twenty-one".