14101021113 has 8 divisors (see below), whose sum is σ = 18806721408. Its totient is φ = 9398000784.

The previous prime is 14101021111. The next prime is 14101021139. The reversal of 14101021113 is 31112010141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14101021113 - 2¹ = 14101021111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14101021092 and 14101021101.

It is not an unprimeable number, because it can be changed into a prime (14101021111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 657681 + ... + 678782.

It is an arithmetic number, because the mean of its divisors is an integer number (2350840176).

Almost surely, 2^14101021113 is an apocalyptic number.

It is an amenable number.

14101021113 is a deficient number, since it is larger than the sum of its proper divisors (4705700295).

14101021113 is a wasteful number, since it uses less digits than its factorization.

14101021113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1339983.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 14101021113 its reverse (31112010141), we get a palindrome (45213031254).

The spelling of 14101021113 in words is "fourteen billion, one hundred one million, twenty-one thousand, one hundred thirteen".