Base | Representation |
---|---|
bin | 100000000011111111001000… |
… | …011000010001001101101101 |
3 | 200111021120011020001122000121 |
4 | 200003333020120101031231 |
5 | 121440312403333201031 |
6 | 1215523431424324541 |
7 | 41462511523552432 |
oct | 4003771030211555 |
9 | 614246136048017 |
10 | 141011433100141 |
11 | 40a2668190852a |
12 | 13994b63773751 |
13 | 608b423564246 |
14 | 26b6dbdd43b89 |
15 | 114806e843011 |
hex | 803fc861136d |
141011433100141 has 32 divisors (see below), whose sum is σ = 144516128440320. Its totient is φ = 137570296449600.
The previous prime is 141011433100099. The next prime is 141011433100159. The reversal of 141011433100141 is 141001334110141.
It is a cyclic number.
It is not a de Polignac number, because 141011433100141 - 211 = 141011433098093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (141011433100541) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 733120180 + ... + 733312498.
It is an arithmetic number, because the mean of its divisors is an integer number (4516129013760).
Almost surely, 2141011433100141 is an apocalyptic number.
It is an amenable number.
141011433100141 is a deficient number, since it is larger than the sum of its proper divisors (3504695340179).
141011433100141 is a wasteful number, since it uses less digits than its factorization.
141011433100141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 192985.
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 141011433100141 its reverse (141001334110141), we get a palindrome (282012767210282).
The spelling of 141011433100141 in words is "one hundred forty-one trillion, eleven billion, four hundred thirty-three million, one hundred thousand, one hundred forty-one".
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