14101155115403 has 2 divisors, whose sum is σ = 14101155115404. Its totient is φ = 14101155115402.

The previous prime is 14101155115379. The next prime is 14101155115469. The reversal of 14101155115403 is 30451155110141.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14101155115403 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14101155115403.

It is not a weakly prime, because it can be changed into another prime (14101155115303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050577557701 + 7050577557702.

It is an arithmetic number, because the mean of its divisors is an integer number (7050577557702).

Almost surely, 2^{14101155115403} is an apocalyptic number.

14101155115403 is a deficient number, since it is larger than the sum of its proper divisors (1).

14101155115403 is an equidigital number, since it uses as much as digits as its factorization.

14101155115403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6000, while the sum is 32.

The spelling of 14101155115403 in words is "fourteen trillion, one hundred one billion, one hundred fifty-five million, one hundred fifteen thousand, four hundred three".