Base | Representation |
---|---|
bin | 10100100001010011101… |
… | …010111000101010000011 |
3 | 11222210211222200212020122 |
4 | 110201103222320222003 |
5 | 141100443133233011 |
6 | 2555452041130455 |
7 | 203610622635335 |
oct | 24412352705203 |
9 | 4883758625218 |
10 | 1410153024131 |
11 | 4a405168a625 |
12 | 1a9369489a2b |
13 | a2c91211867 |
14 | 4c374c03455 |
15 | 26a346983db |
hex | 14853ab8a83 |
1410153024131 has 2 divisors, whose sum is σ = 1410153024132. Its totient is φ = 1410153024130.
The previous prime is 1410153024103. The next prime is 1410153024139. The reversal of 1410153024131 is 1314203510141.
It is a strong prime.
It is an emirp because it is prime and its reverse (1314203510141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1410153024131 - 218 = 1410152761987 is a prime.
It is a super-2 number, since 2×14101530241312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1410153024131.
It is not a weakly prime, because it can be changed into another prime (1410153024139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705076512065 + 705076512066.
It is an arithmetic number, because the mean of its divisors is an integer number (705076512066).
Almost surely, 21410153024131 is an apocalyptic number.
1410153024131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410153024131 is an equidigital number, since it uses as much as digits as its factorization.
1410153024131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 1410153024131 its reverse (1314203510141), we get a palindrome (2724356534272).
The spelling of 1410153024131 in words is "one trillion, four hundred ten billion, one hundred fifty-three million, twenty-four thousand, one hundred thirty-one".
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