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14102013323 = 106621132263
BaseRepresentation
bin11010010001000101…
…11010010110001011
31100101210102111112202
431020202322112023
5212340103411243
610251155030415
71006314064316
oct151042722613
940353374482
1014102013323
115a87245372
12289689b40b
1314397a8ba8
1497ac6d97d
155780844b8
hex3488ba58b

14102013323 has 4 divisors (see below), whose sum is σ = 14102252208. Its totient is φ = 14101774440.

The previous prime is 14102013311. The next prime is 14102013329. The reversal of 14102013323 is 32331020141.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 14102013323 - 210 = 14102012299 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14102013295 and 14102013304.

It is not an unprimeable number, because it can be changed into a prime (14102013329) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40490 + ... + 172752.

It is an arithmetic number, because the mean of its divisors is an integer number (3525563052).

Almost surely, 214102013323 is an apocalyptic number.

14102013323 is a deficient number, since it is larger than the sum of its proper divisors (238885).

14102013323 is a wasteful number, since it uses less digits than its factorization.

14102013323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238884.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 14102013323 its reverse (32331020141), we get a palindrome (46433033464).

The spelling of 14102013323 in words is "fourteen billion, one hundred two million, thirteen thousand, three hundred twenty-three".

Divisors: 1 106621 132263 14102013323