1410259001441 has 2 divisors, whose sum is σ = 1410259001442. Its totient is φ = 1410259001440.

The previous prime is 1410259001407. The next prime is 1410259001453. The reversal of 1410259001441 is 1441009520141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1088850510400 + 321408491041 = 1043480^2 + 566929^2 .

It is a cyclic number.

It is not a de Polignac number, because 1410259001441 - 2⁶ = 1410259001377 is a prime.

It is a super-2 number, since 2×1410259001441² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1410259001398 and 1410259001407.

It is not a weakly prime, because it can be changed into another prime (1410259003441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705129500720 + 705129500721.

It is an arithmetic number, because the mean of its divisors is an integer number (705129500721).

Almost surely, 2^{1410259001441} is an apocalyptic number.

It is an amenable number.

1410259001441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410259001441 is an equidigital number, since it uses as much as digits as its factorization.

1410259001441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 32.

The spelling of 1410259001441 in words is "one trillion, four hundred ten billion, two hundred fifty-nine million, one thousand, four hundred forty-one".