141030465401 has 4 divisors (see below), whose sum is σ = 161177674752. Its totient is φ = 120883256052.

The previous prime is 141030465391. The next prime is 141030465403. The reversal of 141030465401 is 104564030141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141030465401 - 2²² = 141026271097 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141030465403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10073604665 + ... + 10073604678.

It is an arithmetic number, because the mean of its divisors is an integer number (40294418688).

Almost surely, 2^141030465401 is an apocalyptic number.

It is an amenable number.

141030465401 is a deficient number, since it is larger than the sum of its proper divisors (20147209351).

141030465401 is an equidigital number, since it uses as much as digits as its factorization.

141030465401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20147209350.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 141030465401 its reverse (104564030141), we get a palindrome (245594495542).

The spelling of 141030465401 in words is "one hundred forty-one billion, thirty million, four hundred sixty-five thousand, four hundred one".