141040331411521 has 4 divisors (see below), whose sum is σ = 141068410319872. Its totient is φ = 141012252503172.

The previous prime is 141040331411491. The next prime is 141040331411597. The reversal of 141040331411521 is 125114133040141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141040331411521 - 2⁵ = 141040331411489 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141040331441521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14039446641 + ... + 14039456686.

It is an arithmetic number, because the mean of its divisors is an integer number (35267102579968).

Almost surely, 2^{141040331411521} is an apocalyptic number.

It is an amenable number.

141040331411521 is a deficient number, since it is larger than the sum of its proper divisors (28078908351).

141040331411521 is an equidigital number, since it uses as much as digits as its factorization.

141040331411521 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28078908350.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 141040331411521 its reverse (125114133040141), we get a palindrome (266154464451662).

The spelling of 141040331411521 in words is "one hundred forty-one trillion, forty billion, three hundred thirty-one million, four hundred eleven thousand, five hundred twenty-one".