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14104215331 is a prime number
BaseRepresentation
bin11010010001010110…
…10011111100100011
31100101221120101010121
431020223103330203
5212341134342311
610251314141111
71006341565213
oct151053237443
940357511117
1014104215331
115a88509808
122897581797
13143a09a25b
1497b284243
1557836bb71
hex348ad3f23

14104215331 has 2 divisors, whose sum is σ = 14104215332. Its totient is φ = 14104215330.

The previous prime is 14104215313. The next prime is 14104215353. The reversal of 14104215331 is 13351240141.

Together with previous prime (14104215313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14104215331 - 211 = 14104213283 is a prime.

It is a super-2 number, since 2×141042153312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14104215296 and 14104215305.

It is not a weakly prime, because it can be changed into another prime (14104215371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052107665 + 7052107666.

It is an arithmetic number, because the mean of its divisors is an integer number (7052107666).

Almost surely, 214104215331 is an apocalyptic number.

14104215331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14104215331 is an equidigital number, since it uses as much as digits as its factorization.

14104215331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 14104215331 its reverse (13351240141), we get a palindrome (27455455472).

The spelling of 14104215331 in words is "fourteen billion, one hundred four million, two hundred fifteen thousand, three hundred thirty-one".