Base | Representation |
---|---|
bin | 10100100001100100110… |
… | …011010010011000000011 |
3 | 11222211121000112001201212 |
4 | 110201210303102120003 |
5 | 141102040223024144 |
6 | 2555540345320335 |
7 | 203621012631413 |
oct | 24414463223003 |
9 | 4884530461655 |
10 | 1410440439299 |
11 | 4a4189948921 |
12 | 1a94297960ab |
13 | a30089243c8 |
14 | 4c3a105c643 |
15 | 26a4ea1d49e |
hex | 14864cd2603 |
1410440439299 has 2 divisors, whose sum is σ = 1410440439300. Its totient is φ = 1410440439298.
The previous prime is 1410440439283. The next prime is 1410440439319. The reversal of 1410440439299 is 9929340440141.
It is a weak prime.
It is an emirp because it is prime and its reverse (9929340440141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1410440439299 - 24 = 1410440439283 is a prime.
It is a super-2 number, since 2×14104404392992 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1410440439269) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705220219649 + 705220219650.
It is an arithmetic number, because the mean of its divisors is an integer number (705220219650).
Almost surely, 21410440439299 is an apocalyptic number.
1410440439299 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410440439299 is an equidigital number, since it uses as much as digits as its factorization.
1410440439299 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1119744, while the sum is 50.
The spelling of 1410440439299 in words is "one trillion, four hundred ten billion, four hundred forty million, four hundred thirty-nine thousand, two hundred ninety-nine".
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