Base | Representation |
---|---|
bin | 10100100001100100110… |
… | …011010010100011110011 |
3 | 11222211121000112002202201 |
4 | 110201210303102203303 |
5 | 141102040223040201 |
6 | 2555540345324031 |
7 | 203621012633536 |
oct | 24414463224363 |
9 | 4884530462681 |
10 | 1410440440051 |
11 | 4a4189949445 |
12 | 1a9429796617 |
13 | a3008924856 |
14 | 4c3a105ca1d |
15 | 26a4ea1d801 |
hex | 14864cd28f3 |
1410440440051 has 2 divisors, whose sum is σ = 1410440440052. Its totient is φ = 1410440440050.
The previous prime is 1410440439943. The next prime is 1410440440069. The reversal of 1410440440051 is 1500440440141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1410440440051 - 27 = 1410440439923 is a prime.
It is not a weakly prime, because it can be changed into another prime (1410440140051) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705220220025 + 705220220026.
It is an arithmetic number, because the mean of its divisors is an integer number (705220220026).
Almost surely, 21410440440051 is an apocalyptic number.
1410440440051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410440440051 is an equidigital number, since it uses as much as digits as its factorization.
1410440440051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5120, while the sum is 28.
Adding to 1410440440051 its reverse (1500440440141), we get a palindrome (2910880880192).
The spelling of 1410440440051 in words is "one trillion, four hundred ten billion, four hundred forty million, four hundred forty thousand, fifty-one".
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