Base | Representation |
---|---|
bin | 1100110100111111000110… |
… | …1000000011110111101001 |
3 | 1211221101000002002221120210 |
4 | 3031033301220003313221 |
5 | 3322041333422142213 |
6 | 45555253015211333 |
7 | 2654003650104162 |
oct | 315176150036751 |
9 | 54841002087523 |
10 | 14104431443433 |
11 | 4548723936831 |
12 | 16b9649676b49 |
13 | 7b4071885666 |
14 | 36a92dc70769 |
15 | 196d4e1d30c3 |
hex | cd3f1a03de9 |
14104431443433 has 32 divisors (see below), whose sum is σ = 19937876886144. Its totient is φ = 8838404370432.
The previous prime is 14104431443429. The next prime is 14104431443527. The reversal of 14104431443433 is 33434413440141.
It is not a de Polignac number, because 14104431443433 - 22 = 14104431443429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14104431443391 and 14104431443400.
It is not an unprimeable number, because it can be changed into a prime (14104431443033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 228725541 + ... + 228787197.
It is an arithmetic number, because the mean of its divisors is an integer number (623058652692).
Almost surely, 214104431443433 is an apocalyptic number.
It is an amenable number.
14104431443433 is a deficient number, since it is larger than the sum of its proper divisors (5833445442711).
14104431443433 is a wasteful number, since it uses less digits than its factorization.
14104431443433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67401.
The product of its (nonzero) digits is 331776, while the sum is 39.
Adding to 14104431443433 its reverse (33434413440141), we get a palindrome (47538844883574).
The spelling of 14104431443433 in words is "fourteen trillion, one hundred four billion, four hundred thirty-one million, four hundred forty-three thousand, four hundred thirty-three".
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