141053255305403 has 4 divisors (see below), whose sum is σ = 161203720349040. Its totient is φ = 120902790261768.

The previous prime is 141053255305399. The next prime is 141053255305463. The reversal of 141053255305403 is 304503552350141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141053255305403 - 2² = 141053255305399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141053255305463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10075232521808 + ... + 10075232521821.

It is an arithmetic number, because the mean of its divisors is an integer number (40300930087260).

Almost surely, 2^{141053255305403} is an apocalyptic number.

141053255305403 is a deficient number, since it is larger than the sum of its proper divisors (20150465043637).

141053255305403 is an equidigital number, since it uses as much as digits as its factorization.

141053255305403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20150465043636.

The product of its (nonzero) digits is 540000, while the sum is 41.

The spelling of 141053255305403 in words is "one hundred forty-one trillion, fifty-three billion, two hundred fifty-five million, three hundred five thousand, four hundred three".