Base | Representation |
---|---|
bin | 100000000100100111011101… |
… | …101010010001001110110110 |
3 | 200111102200221100021121012220 |
4 | 200010213131222101032312 |
5 | 121442020101343011202 |
6 | 1215555353005423210 |
7 | 41465603642545410 |
oct | 4004473552211666 |
9 | 614380840247186 |
10 | 141054739813302 |
11 | 40a42a85376067 |
12 | 139a142ab6ab06 |
13 | 60925357095c3 |
14 | 26b912b7579b0 |
15 | 11492567a6abc |
hex | 8049dda913b6 |
141054739813302 has 64 divisors (see below), whose sum is σ = 325463261220864. Its totient is φ = 39919891652640.
The previous prime is 141054739813297. The next prime is 141054739813319. The reversal of 141054739813302 is 203318937450141.
141054739813302 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1410547398133022 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35461333 + ... + 39237935.
It is an arithmetic number, because the mean of its divisors is an integer number (5085363456576).
Almost surely, 2141054739813302 is an apocalyptic number.
141054739813302 is an abundant number, since it is smaller than the sum of its proper divisors (184408521407562).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141054739813302 is a wasteful number, since it uses less digits than its factorization.
141054739813302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3785033.
The product of its (nonzero) digits is 2177280, while the sum is 51.
The spelling of 141054739813302 in words is "one hundred forty-one trillion, fifty-four billion, seven hundred thirty-nine million, eight hundred thirteen thousand, three hundred two".
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