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14110034214403 = 31455162394013
BaseRepresentation
bin1100110101010011111110…
…0100111011111000000011
31211221220110112201012110201
43031110333210323320003
53322134322224330103
650002021002110031
72654262541631341
oct315247744737003
954856415635421
1014110034214403
114550039514566
1216ba751aab317
137b475557015a
1436ad01dda991
1519707b00351d
hexcd53f93be03

14110034214403 has 4 divisors (see below), whose sum is σ = 14565196608448. Its totient is φ = 13654871820360.

The previous prime is 14110034214391. The next prime is 14110034214443. The reversal of 14110034214403 is 30441243001141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14110034214403 - 237 = 13972595260931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14110034214443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 227581196976 + ... + 227581197037.

It is an arithmetic number, because the mean of its divisors is an integer number (3641299152112).

Almost surely, 214110034214403 is an apocalyptic number.

14110034214403 is a deficient number, since it is larger than the sum of its proper divisors (455162394045).

14110034214403 is an equidigital number, since it uses as much as digits as its factorization.

14110034214403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 455162394044.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 14110034214403 its reverse (30441243001141), we get a palindrome (44551277215544).

The spelling of 14110034214403 in words is "fourteen trillion, one hundred ten billion, thirty-four million, two hundred fourteen thousand, four hundred three".

Divisors: 1 31 455162394013 14110034214403