Base | Representation |
---|---|
bin | 1100110101010100000000… |
… | …1010010100001100110011 |
3 | 1211221220111020011001010011 |
4 | 3031111000022110030303 |
5 | 3322134332231411423 |
6 | 50002021552115351 |
7 | 2654263021132624 |
oct | 315250012241463 |
9 | 54856436131104 |
10 | 14110044013363 |
11 | 4550043aa7681 |
12 | 16ba755235b57 |
13 | 7b47575c135c |
14 | 36ad0342ba4b |
15 | 19707bcdbb0d |
hex | cd540294333 |
14110044013363 has 2 divisors, whose sum is σ = 14110044013364. Its totient is φ = 14110044013362.
The previous prime is 14110044013291. The next prime is 14110044013397. The reversal of 14110044013363 is 36331044001141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14110044013363 is a prime.
It is a super-2 number, since 2×141100440133632 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (14110048013363) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055022006681 + 7055022006682.
It is an arithmetic number, because the mean of its divisors is an integer number (7055022006682).
Almost surely, 214110044013363 is an apocalyptic number.
14110044013363 is a deficient number, since it is larger than the sum of its proper divisors (1).
14110044013363 is an equidigital number, since it uses as much as digits as its factorization.
14110044013363 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 31.
The spelling of 14110044013363 in words is "fourteen trillion, one hundred ten billion, forty-four million, thirteen thousand, three hundred sixty-three".
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