1411021113 has 4 divisors (see below), whose sum is σ = 1881361488. Its totient is φ = 940680740.

The previous prime is 1411021099. The next prime is 1411021123. The reversal of 1411021113 is 3111201141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1411021113 - 2⁵ = 1411021081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1411021092 and 1411021101.

It is not an unprimeable number, because it can be changed into a prime (1411021123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 235170183 + ... + 235170188.

It is an arithmetic number, because the mean of its divisors is an integer number (470340372).

Almost surely, 2^1411021113 is an apocalyptic number.

It is an amenable number.

1411021113 is a deficient number, since it is larger than the sum of its proper divisors (470340375).

1411021113 is an equidigital number, since it uses as much as digits as its factorization.

1411021113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 470340374.

The product of its (nonzero) digits is 24, while the sum is 15.

The square root of 1411021113 is about 37563.5609733689. The cubic root of 1411021113 is about 1121.6167957160.

Adding to 1411021113 its reverse (3111201141), we get a palindrome (4522222254).

The spelling of 1411021113 in words is "one billion, four hundred eleven million, twenty-one thousand, one hundred thirteen".