Base | Representation |
---|---|
bin | 10100100010001000000… |
… | …000100111000001011111 |
3 | 11222220010012000110221121 |
4 | 110202020000213001133 |
5 | 141104242432244203 |
6 | 3000115130111411 |
7 | 203641444514320 |
oct | 24421000470137 |
9 | 4886105013847 |
10 | 1411031134303 |
11 | 4a446232080a |
12 | 1a957357b567 |
13 | a30a111288b |
14 | 4c4196a2447 |
15 | 26a867ee0bd |
hex | 1488802705f |
1411031134303 has 16 divisors (see below), whose sum is σ = 1628352101376. Its totient is φ = 1197647720640.
The previous prime is 1411031134207. The next prime is 1411031134367. The reversal of 1411031134303 is 3034311301141.
It is not a de Polignac number, because 1411031134303 - 213 = 1411031126111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1411031134003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16945950 + ... + 17029012.
It is an arithmetic number, because the mean of its divisors is an integer number (101772006336).
Almost surely, 21411031134303 is an apocalyptic number.
1411031134303 is a deficient number, since it is larger than the sum of its proper divisors (217320967073).
1411031134303 is a wasteful number, since it uses less digits than its factorization.
1411031134303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106734.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1411031134303 its reverse (3034311301141), we get a palindrome (4445342435444).
The spelling of 1411031134303 in words is "one trillion, four hundred eleven billion, thirty-one million, one hundred thirty-four thousand, three hundred three".
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