1411041001241 has 4 divisors (see below), whose sum is σ = 1411044748800. Its totient is φ = 1411037253684.

The previous prime is 1411041001147. The next prime is 1411041001267. The reversal of 1411041001241 is 1421001401141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1411041001241 - 2¹⁰ = 1411041000217 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1411041001441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1236821 + ... + 2086098.

It is an arithmetic number, because the mean of its divisors is an integer number (352761187200).

Almost surely, 2^{1411041001241} is an apocalyptic number.

It is an amenable number.

1411041001241 is a deficient number, since it is larger than the sum of its proper divisors (3747559).

1411041001241 is an equidigital number, since it uses as much as digits as its factorization.

1411041001241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3747558.

The product of its (nonzero) digits is 128, while the sum is 20.

Adding to 1411041001241 its reverse (1421001401141), we get a palindrome (2832042402382).

The spelling of 1411041001241 in words is "one trillion, four hundred eleven billion, forty-one million, one thousand, two hundred forty-one".