Base | Representation |
---|---|
bin | 1000001101101001110… |
… | …1011110100111100011 |
3 | 111111012210021200121202 |
4 | 2003122131132213203 |
5 | 4302440123123042 |
6 | 144453342511415 |
7 | 13123456115663 |
oct | 2033235364743 |
9 | 444183250552 |
10 | 141104114147 |
11 | 54929659477 |
12 | 2341b59556b |
13 | 103c9553489 |
14 | 6b8811c1a3 |
15 | 3a0cb1b632 |
hex | 20da75e9e3 |
141104114147 has 2 divisors, whose sum is σ = 141104114148. Its totient is φ = 141104114146.
The previous prime is 141104114141. The next prime is 141104114231. The reversal of 141104114147 is 741411401141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141104114147 - 228 = 140835678691 is a prime.
It is not a weakly prime, because it can be changed into another prime (141104114141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70552057073 + 70552057074.
It is an arithmetic number, because the mean of its divisors is an integer number (70552057074).
Almost surely, 2141104114147 is an apocalyptic number.
141104114147 is a deficient number, since it is larger than the sum of its proper divisors (1).
141104114147 is an equidigital number, since it uses as much as digits as its factorization.
141104114147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 29.
Adding to 141104114147 its reverse (741411401141), we get a palindrome (882515515288).
The spelling of 141104114147 in words is "one hundred forty-one billion, one hundred four million, one hundred fourteen thousand, one hundred forty-seven".
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