Base | Representation |
---|---|
bin | 1100110101010101011000… |
… | …0110100100011100100011 |
3 | 1211221221102212211022022202 |
4 | 3031111112012210130203 |
5 | 3322141111001130313 |
6 | 50002122302123415 |
7 | 2654305111103333 |
oct | 315252606443443 |
9 | 54857385738282 |
10 | 14110412130083 |
11 | 4550212876175 |
12 | 16ba83858056b |
13 | 7b47b594b6b9 |
14 | 36ad3a2930c3 |
15 | 19709e2a3558 |
hex | cd5561a4723 |
14110412130083 has 2 divisors, whose sum is σ = 14110412130084. Its totient is φ = 14110412130082.
The previous prime is 14110412130043. The next prime is 14110412130119. The reversal of 14110412130083 is 38003121401141.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14110412130083 is a prime.
It is not a weakly prime, because it can be changed into another prime (14110412130043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055206065041 + 7055206065042.
It is an arithmetic number, because the mean of its divisors is an integer number (7055206065042).
Almost surely, 214110412130083 is an apocalyptic number.
14110412130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
14110412130083 is an equidigital number, since it uses as much as digits as its factorization.
14110412130083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 29.
The spelling of 14110412130083 in words is "fourteen trillion, one hundred ten billion, four hundred twelve million, one hundred thirty thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.108 sec. • engine limits •