141111403 has 4 divisors (see below), whose sum is σ = 141727840. Its totient is φ = 140494968.

The previous prime is 141111359. The next prime is 141111413. The reversal of 141111403 is 304111141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304111141 = 5303 ⋅57347.

It is a cyclic number.

It is not a de Polignac number, because 141111403 - 2¹⁷ = 140980331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141111413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 307875 + ... + 308332.

It is an arithmetic number, because the mean of its divisors is an integer number (35431960).

Almost surely, 2^141111403 is an apocalyptic number.

141111403 is a deficient number, since it is larger than the sum of its proper divisors (616437).

141111403 is an equidigital number, since it uses as much as digits as its factorization.

141111403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 616436.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 141111403 is about 11879.0320733636. The cubic root of 141111403 is about 520.6198267172.

Adding to 141111403 its reverse (304111141), we get a palindrome (445222544).

The spelling of 141111403 in words is "one hundred forty-one million, one hundred eleven thousand, four hundred three".