Search a number
-
+
1411123533137 is a prime number
BaseRepresentation
bin10100100010001101100…
…001000101010101010001
311222220100121212211022122
4110202031201011111101
5141104440111030022
63000132230344025
7203643646060553
oct24421541052521
94886317784278
101411123533137
114a44aa4a038a
121a959a4bb015
13a30b72c4646
144c427a754d3
1526a8e9a1742
hex1488d845551

1411123533137 has 2 divisors, whose sum is σ = 1411123533138. Its totient is φ = 1411123533136.

The previous prime is 1411123532993. The next prime is 1411123533143. The reversal of 1411123533137 is 7313353211141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1409517447361 + 1606085776 = 1187231^2 + 40076^2 .

It is an emirp because it is prime and its reverse (7313353211141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1411123533137 - 210 = 1411123532113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1411123533097 and 1411123533106.

It is not a weakly prime, because it can be changed into another prime (1411123533187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705561766568 + 705561766569.

It is an arithmetic number, because the mean of its divisors is an integer number (705561766569).

Almost surely, 21411123533137 is an apocalyptic number.

It is an amenable number.

1411123533137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411123533137 is an equidigital number, since it uses as much as digits as its factorization.

1411123533137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 22680, while the sum is 35.

Adding to 1411123533137 its reverse (7313353211141), we get a palindrome (8724476744278).

The spelling of 1411123533137 in words is "one trillion, four hundred eleven billion, one hundred twenty-three million, five hundred thirty-three thousand, one hundred thirty-seven".