141113000233 has 4 divisors (see below), whose sum is σ = 141116019088. Its totient is φ = 141109981380.

The previous prime is 141113000191. The next prime is 141113000239. The reversal of 141113000233 is 332000311141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 332000311141 = 463 ⋅717063307.

It is a cyclic number.

It is not a de Polignac number, because 141113000233 - 2²¹ = 141110903081 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141113000233.

It is not an unprimeable number, because it can be changed into a prime (141113000239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1438191 + ... + 1533172.

It is an arithmetic number, because the mean of its divisors is an integer number (35279004772).

Almost surely, 2^141113000233 is an apocalyptic number.

It is an amenable number.

141113000233 is a deficient number, since it is larger than the sum of its proper divisors (3018855).

141113000233 is an equidigital number, since it uses as much as digits as its factorization.

141113000233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3018854.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 141113000233 its reverse (332000311141), we get a palindrome (473113311374).

The spelling of 141113000233 in words is "one hundred forty-one billion, one hundred thirteen million, two hundred thirty-three", and thus it is an aban number.