Base | Representation |
---|---|
bin | 1100110101011001011110… |
… | …1110111000000000111010 |
3 | 1211222001021121201012220212 |
4 | 3031112113232320000322 |
5 | 3322200334340340114 |
6 | 50002423434151122 |
7 | 2654344311135464 |
oct | 315262756700072 |
9 | 54861247635825 |
10 | 14111513215034 |
11 | 4550728361634 |
12 | 16baaa52824a2 |
13 | 7b492cabc161 |
14 | 36b0025d5134 |
15 | 197115ca0b3e |
hex | cd597bb803a |
14111513215034 has 32 divisors (see below), whose sum is σ = 22079825510400. Its totient is φ = 6759390138480.
The previous prime is 14111513215031. The next prime is 14111513215087. The reversal of 14111513215034 is 43051231511141.
It is a super-3 number, since 3×141115132150343 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (14111513215031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6678074 + ... + 8533445.
It is an arithmetic number, because the mean of its divisors is an integer number (689994547200).
Almost surely, 214111513215034 is an apocalyptic number.
14111513215034 is a deficient number, since it is larger than the sum of its proper divisors (7968312295366).
14111513215034 is a wasteful number, since it uses less digits than its factorization.
14111513215034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15211778.
The product of its (nonzero) digits is 7200, while the sum is 32.
Adding to 14111513215034 its reverse (43051231511141), we get a palindrome (57162744726175).
The spelling of 14111513215034 in words is "fourteen trillion, one hundred eleven billion, five hundred thirteen million, two hundred fifteen thousand, thirty-four".
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