Base | Representation |
---|---|
bin | 1100110101011001100000… |
… | …1110000111100101111011 |
3 | 1211222001022012010022212022 |
4 | 3031112120032013211323 |
5 | 3322200343434432212 |
6 | 50002424325505055 |
7 | 2654344440560024 |
oct | 315263016074573 |
9 | 54861265108768 |
10 | 14111521405307 |
11 | 4550731a46057 |
12 | 16baaa7b7218b |
13 | 7b49316c9081 |
14 | 36b003727c4b |
15 | 19711686c772 |
hex | cd59838797b |
14111521405307 has 2 divisors, whose sum is σ = 14111521405308. Its totient is φ = 14111521405306.
The previous prime is 14111521405253. The next prime is 14111521405343. The reversal of 14111521405307 is 70350412511141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14111521405307 - 230 = 14110447663483 is a prime.
It is not a weakly prime, because it can be changed into another prime (14111521405357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055760702653 + 7055760702654.
It is an arithmetic number, because the mean of its divisors is an integer number (7055760702654).
Almost surely, 214111521405307 is an apocalyptic number.
14111521405307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111521405307 is an equidigital number, since it uses as much as digits as its factorization.
14111521405307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 35.
Adding to 14111521405307 its reverse (70350412511141), we get a palindrome (84461933916448).
The spelling of 14111521405307 in words is "fourteen trillion, one hundred eleven billion, five hundred twenty-one million, four hundred five thousand, three hundred seven".
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