Base | Representation |
---|---|
bin | 1100110101011001100001… |
… | …0000100011111001000011 |
3 | 1211222001022020022212001102 |
4 | 3031112120100203321003 |
5 | 3322200344120424012 |
6 | 50002424351325015 |
7 | 2654344446164345 |
oct | 315263020437103 |
9 | 54861266285042 |
10 | 14111522045507 |
11 | 4550732343047 |
12 | 16baaa822076b |
13 | 7b49318915a3 |
14 | 36b003853295 |
15 | 1971169472c2 |
hex | cd598423e43 |
14111522045507 has 2 divisors, whose sum is σ = 14111522045508. Its totient is φ = 14111522045506.
The previous prime is 14111522045477. The next prime is 14111522045557. The reversal of 14111522045507 is 70554022511141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14111522045507 - 212 = 14111522041411 is a prime.
It is not a weakly prime, because it can be changed into another prime (14111522045557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055761022753 + 7055761022754.
It is an arithmetic number, because the mean of its divisors is an integer number (7055761022754).
Almost surely, 214111522045507 is an apocalyptic number.
14111522045507 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111522045507 is an equidigital number, since it uses as much as digits as its factorization.
14111522045507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56000, while the sum is 38.
Adding to 14111522045507 its reverse (70554022511141), we get a palindrome (84665544556648).
The spelling of 14111522045507 in words is "fourteen trillion, one hundred eleven billion, five hundred twenty-two million, forty-five thousand, five hundred seven".
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