Base | Representation |
---|---|
bin | 11010010010010010… |
… | …00000100110011110 |
3 | 1100102111012220021000 |
4 | 31021021000212132 |
5 | 212400133003124 |
6 | 10252153051130 |
7 | 1006465011231 |
oct | 151111004636 |
9 | 40374186230 |
10 | 14112000414 |
11 | 5a91946866 |
12 | 289a0b6aa6 |
13 | 143b894905 |
14 | 97c30d418 |
15 | 578da86c9 |
hex | 34924099e |
14112000414 has 32 divisors (see below), whose sum is σ = 31599406080. Its totient is φ = 4668089400.
The previous prime is 14112000403. The next prime is 14112000431. The reversal of 14112000414 is 41400021141.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 990382 + ... + 1004529.
It is an arithmetic number, because the mean of its divisors is an integer number (987481440).
Almost surely, 214112000414 is an apocalyptic number.
14112000414 is an abundant number, since it is smaller than the sum of its proper divisors (17487405666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112000414 is a wasteful number, since it uses less digits than its factorization.
14112000414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1995053 (or 1995047 counting only the distinct ones).
The product of its (nonzero) digits is 128, while the sum is 18.
Adding to 14112000414 its reverse (41400021141), we get a palindrome (55512021555).
The spelling of 14112000414 in words is "fourteen billion, one hundred twelve million, four hundred fourteen", and thus it is an aban number.
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