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141120245001 = 347040081667
BaseRepresentation
bin1000001101101101101…
…1000000110100001001
3111111020220122012222210
42003123123000310021
54303003240320001
6144455120335333
713124043201501
oct2033333006411
9444226565883
10141120245001
115493777685a
1223424a74549
13103cc9b0768
146b8a31aa01
153a0e255dd6
hex20db6c0d09

141120245001 has 4 divisors (see below), whose sum is σ = 188160326672. Its totient is φ = 94080163332.

The previous prime is 141120244963. The next prime is 141120245041. The reversal of 141120245001 is 100542021141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100542021141 = 333514007047.

It is not a de Polignac number, because 141120245001 - 226 = 141053136137 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141120245041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23520040831 + ... + 23520040836.

It is an arithmetic number, because the mean of its divisors is an integer number (47040081668).

Almost surely, 2141120245001 is an apocalyptic number.

It is an amenable number.

141120245001 is a deficient number, since it is larger than the sum of its proper divisors (47040081671).

141120245001 is an equidigital number, since it uses as much as digits as its factorization.

141120245001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47040081670.

The product of its (nonzero) digits is 320, while the sum is 21.

Adding to 141120245001 its reverse (100542021141), we get a palindrome (241662266142).

The spelling of 141120245001 in words is "one hundred forty-one billion, one hundred twenty million, two hundred forty-five thousand, one".

Divisors: 1 3 47040081667 141120245001