141120302024113 has 8 divisors (see below), whose sum is σ = 143230808579040. Its totient is φ = 139009919980800.

The previous prime is 141120302024089. The next prime is 141120302024123. The reversal of 141120302024113 is 311420203021141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141120302024113 - 2⁵ = 141120302024081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141120302024123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28842928 + ... + 33378961.

It is an arithmetic number, because the mean of its divisors is an integer number (17903851072380).

Almost surely, 2^{141120302024113} is an apocalyptic number.

It is an amenable number.

141120302024113 is a deficient number, since it is larger than the sum of its proper divisors (2110506554927).

141120302024113 is an equidigital number, since it uses as much as digits as its factorization.

141120302024113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62255807.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 141120302024113 its reverse (311420203021141), we get a palindrome (452540505045254).

The spelling of 141120302024113 in words is "one hundred forty-one trillion, one hundred twenty billion, three hundred two million, twenty-four thousand, one hundred thirteen".