141121042143331 has 8 divisors (see below), whose sum is σ = 141577911584928. Its totient is φ = 140664192600000.

The previous prime is 141121042143311. The next prime is 141121042143359. The reversal of 141121042143331 is 133341240121141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141121042143331 - 2⁴⁵ = 105936670054499 is a prime.

It is a super-2 number, since 2×141121042143331² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141121042143293 and 141121042143302.

It is not an unprimeable number, because it can be changed into a prime (141121042143311) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9298831 + ... + 19201831.

It is an arithmetic number, because the mean of its divisors is an integer number (17697238948116).

Almost surely, 2^{141121042143331} is an apocalyptic number.

141121042143331 is a deficient number, since it is larger than the sum of its proper divisors (456869441597).

141121042143331 is an equidigital number, since it uses as much as digits as its factorization.

141121042143331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9949133.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 141121042143331 its reverse (133341240121141), we get a palindrome (274462282264472).

The spelling of 141121042143331 in words is "one hundred forty-one trillion, one hundred twenty-one billion, forty-two million, one hundred forty-three thousand, three hundred thirty-one".