Base | Representation |
---|---|
bin | 1100110101011011101100… |
… | …0010011110010001000011 |
3 | 1211222002210220022012121112 |
4 | 3031112323002132101003 |
5 | 3322203043010230021 |
6 | 50003002314113535 |
7 | 2654365063012262 |
oct | 315267302362103 |
9 | 54862726265545 |
10 | 14112105555011 |
11 | 4550a01758402 |
12 | 16bb02b71b8ab |
13 | 7b49c5735299 |
14 | 36b05b1465d9 |
15 | 19714cca8d5b |
hex | cd5bb09e443 |
14112105555011 has 2 divisors, whose sum is σ = 14112105555012. Its totient is φ = 14112105555010.
The previous prime is 14112105554957. The next prime is 14112105555017. The reversal of 14112105555011 is 11055550121141.
14112105555011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14112105555011 - 26 = 14112105554947 is a prime.
It is not a weakly prime, because it can be changed into another prime (14112105555017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056052777505 + 7056052777506.
It is an arithmetic number, because the mean of its divisors is an integer number (7056052777506).
Almost surely, 214112105555011 is an apocalyptic number.
14112105555011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14112105555011 is an equidigital number, since it uses as much as digits as its factorization.
14112105555011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5000, while the sum is 32.
Adding to 14112105555011 its reverse (11055550121141), we get a palindrome (25167655676152).
The spelling of 14112105555011 in words is "fourteen trillion, one hundred twelve billion, one hundred five million, five hundred fifty-five thousand, eleven".
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