141121114240313 has 4 divisors (see below), whose sum is σ = 141121168648740. Its totient is φ = 141121059831888.

The previous prime is 141121114240297. The next prime is 141121114240319. The reversal of 141121114240313 is 313042411121141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 15816552862009 + 125304561378304 = 3977003^2 + 11193952^2 .

It is a cyclic number.

It is not a de Polignac number, because 141121114240313 - 2⁴ = 141121114240297 is a prime.

It is a super-2 number, since 2×141121114240313² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141121114240319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23108018 + ... + 28569611.

It is an arithmetic number, because the mean of its divisors is an integer number (35280292162185).

Almost surely, 2^{141121114240313} is an apocalyptic number.

It is an amenable number.

141121114240313 is a deficient number, since it is larger than the sum of its proper divisors (54408427).

141121114240313 is an equidigital number, since it uses as much as digits as its factorization.

141121114240313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54408426.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 141121114240313 its reverse (313042411121141), we get a palindrome (454163525361454).

The spelling of 141121114240313 in words is "one hundred forty-one trillion, one hundred twenty-one billion, one hundred fourteen million, two hundred forty thousand, three hundred thirteen".