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14112144003 = 36177115541
BaseRepresentation
bin11010010010010011…
…00011101010000011
31100102111111012020010
431021021203222003
5212400202102003
610252200120003
71006466146656
oct151111435203
940374435203
1014112144003
115a91a34731
12289a166003
13143b915089
1497c34989d
15578dd6003
hex349263a83

14112144003 has 8 divisors (see below), whose sum is σ = 19124654416. Its totient is φ = 9253864800.

The previous prime is 14112143987. The next prime is 14112144019. The reversal of 14112144003 is 30044121141.

It is an interprime number because it is at equal distance from previous prime (14112143987) and next prime (14112144019).

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14112144003 - 24 = 14112143987 is a prime.

It is a super-2 number, since 2×141121440032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14112154003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38557588 + ... + 38557953.

It is an arithmetic number, because the mean of its divisors is an integer number (2390581802).

Almost surely, 214112144003 is an apocalyptic number.

14112144003 is a deficient number, since it is larger than the sum of its proper divisors (5012510413).

14112144003 is an equidigital number, since it uses as much as digits as its factorization.

14112144003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77115605.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14112144003 its reverse (30044121141), we get a palindrome (44156265144).

The spelling of 14112144003 in words is "fourteen billion, one hundred twelve million, one hundred forty-four thousand, three".

Divisors: 1 3 61 183 77115541 231346623 4704048001 14112144003