Base | Representation |
---|---|
bin | 11010010010010101… |
… | …00010011011100011 |
3 | 1100102111222020221002 |
4 | 31021022202123203 |
5 | 212400233313443 |
6 | 10252205422215 |
7 | 1006501300412 |
oct | 151112423343 |
9 | 40374866832 |
10 | 14112401123 |
11 | 5a9209a927 |
12 | 289a26a96b |
13 | 143b9a5112 |
14 | 97c3b5479 |
15 | 578e372b8 |
hex | 3492a26e3 |
14112401123 has 4 divisors (see below), whose sum is σ = 14311167408. Its totient is φ = 13913634840.
The previous prime is 14112401119. The next prime is 14112401141. The reversal of 14112401123 is 32110421141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14112401123 - 22 = 14112401119 is a prime.
It is a super-2 number, since 2×141124011232 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14112401095 and 14112401104.
It is not an unprimeable number, because it can be changed into a prime (14112401623) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 99383036 + ... + 99383177.
It is an arithmetic number, because the mean of its divisors is an integer number (3577791852).
Almost surely, 214112401123 is an apocalyptic number.
14112401123 is a deficient number, since it is larger than the sum of its proper divisors (198766285).
14112401123 is an equidigital number, since it uses as much as digits as its factorization.
14112401123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 198766284.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 14112401123 its reverse (32110421141), we get a palindrome (46222822264).
The spelling of 14112401123 in words is "fourteen billion, one hundred twelve million, four hundred one thousand, one hundred twenty-three".
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