Search a number
-
+
14112424433 = 231636176101
BaseRepresentation
bin11010010010010101…
…01000000111110001
31100102112000102220102
431021022220013301
5212400240040213
610252210122145
71006501425362
oct151112500761
940375012812
1014112424433
115a92106398
12289a280355
13143b9b2903
1497c3bdb69
15578e3e158
hex3492a81f1

14112424433 has 16 divisors (see below), whose sum is σ = 14842797696. Its totient is φ = 13392086400.

The previous prime is 14112424429. The next prime is 14112424441. The reversal of 14112424433 is 33442421141.

It is a cyclic number.

It is not a de Polignac number, because 14112424433 - 22 = 14112424429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112424396 and 14112424405.

It is not an unprimeable number, because it can be changed into a prime (14112424453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2310083 + ... + 2316183.

It is an arithmetic number, because the mean of its divisors is an integer number (927674856).

Almost surely, 214112424433 is an apocalyptic number.

It is an amenable number.

14112424433 is a deficient number, since it is larger than the sum of its proper divisors (730373263).

14112424433 is a wasteful number, since it uses less digits than its factorization.

14112424433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6904.

The product of its digits is 9216, while the sum is 29.

Adding to 14112424433 its reverse (33442421141), we get a palindrome (47554845574).

The spelling of 14112424433 in words is "fourteen billion, one hundred twelve million, four hundred twenty-four thousand, four hundred thirty-three".

Divisors: 1 23 163 617 3749 6101 14191 100571 140323 994463 2313133 3764317 22872649 86579291 613583671 14112424433