Search a number
-
+
141124320503513 is a prime number
BaseRepresentation
bin100000000101101000010000…
…111111100010011011011001
3200111200100112112121220012022
4200011220100333202123121
5121444140102022103023
61220051341241224225
741503616135630504
oct4005502077423331
9614610475556168
10141124320503513
1140a6a540903516
12139b2a09492075
136098c74011449
1426bc64c7c013b
15114ae7a18c7c8
hex805a10fe26d9

141124320503513 has 2 divisors, whose sum is σ = 141124320503514. Its totient is φ = 141124320503512.

The previous prime is 141124320503483. The next prime is 141124320503521. The reversal of 141124320503513 is 315305023421141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75619772497369 + 65504548006144 = 8695963^2 + 8093488^2 .

It is a cyclic number.

It is not a de Polignac number, because 141124320503513 - 216 = 141124320437977 is a prime.

It is not a weakly prime, because it can be changed into another prime (141124320503113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70562160251756 + 70562160251757.

It is an arithmetic number, because the mean of its divisors is an integer number (70562160251757).

Almost surely, 2141124320503513 is an apocalyptic number.

It is an amenable number.

141124320503513 is a deficient number, since it is larger than the sum of its proper divisors (1).

141124320503513 is an equidigital number, since it uses as much as digits as its factorization.

141124320503513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 141124320503513 its reverse (315305023421141), we get a palindrome (456429343924654).

The spelling of 141124320503513 in words is "one hundred forty-one trillion, one hundred twenty-four billion, three hundred twenty million, five hundred three thousand, five hundred thirteen".