Base | Representation |
---|---|
bin | 11010010010010101… |
… | …01111100101100101 |
3 | 1100102112001222212000 |
4 | 31021022233211211 |
5 | 212400242030023 |
6 | 10252210515513 |
7 | 1006501613466 |
oct | 151112574545 |
9 | 40375058760 |
10 | 14112455013 |
11 | 5a92127368 |
12 | 289a295b99 |
13 | 143b9c37c7 |
14 | 97c3cad6d |
15 | 578e48243 |
hex | 3492af965 |
14112455013 has 16 divisors (see below), whose sum is σ = 20934989760. Its totient is φ = 9395861328.
The previous prime is 14112454997. The next prime is 14112455033. The reversal of 14112455013 is 31055421141.
14112455013 is a `hidden beast` number, since 1 + 4 + 112 + 45 + 501 + 3 = 666.
It is not a de Polignac number, because 14112455013 - 24 = 14112454997 is a prime.
It is a super-2 number, since 2×141124550132 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112455033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 324795 + ... + 365672.
It is an arithmetic number, because the mean of its divisors is an integer number (1308436860).
Almost surely, 214112455013 is an apocalyptic number.
It is an amenable number.
14112455013 is a deficient number, since it is larger than the sum of its proper divisors (6822534747).
14112455013 is an equidigital number, since it uses as much as digits as its factorization.
14112455013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 691233 (or 691227 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 27.
Adding to 14112455013 its reverse (31055421141), we get a palindrome (45167876154).
The spelling of 14112455013 in words is "fourteen billion, one hundred twelve million, four hundred fifty-five thousand, thirteen".
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