Base | Representation |
---|---|
bin | 1100110101011101001100… |
… | …1110101111001000011010 |
3 | 1211222010212012000102211100 |
4 | 3031113103032233020122 |
5 | 3322204410411014002 |
6 | 50003110453212230 |
7 | 2654411121564006 |
oct | 315272316571032 |
9 | 54863765012740 |
10 | 14112511423002 |
11 | 455109a870aa3 |
12 | 16bb123631076 |
13 | 7b4a5b84c765 |
14 | 36b098dd7706 |
15 | 19717372b11c |
hex | cd5d33af21a |
14112511423002 has 48 divisors (see below), whose sum is σ = 32508557947008. Its totient is φ = 4414742423520.
The previous prime is 14112511423001. The next prime is 14112511423007. The reversal of 14112511423002 is 20032411521141.
14112511423002 is a `hidden beast` number, since 1 + 4 + 112 + 511 + 4 + 2 + 30 + 0 + 2 = 666.
It is not an unprimeable number, because it can be changed into a prime (14112511423001) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 321564774 + ... + 321608657.
It is an arithmetic number, because the mean of its divisors is an integer number (677261623896).
Almost surely, 214112511423002 is an apocalyptic number.
14112511423002 is an abundant number, since it is smaller than the sum of its proper divisors (18396046524006).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14112511423002 is a wasteful number, since it uses less digits than its factorization.
14112511423002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 643173515 (or 643173512 counting only the distinct ones).
The product of its (nonzero) digits is 1920, while the sum is 27.
Adding to 14112511423002 its reverse (20032411521141), we get a palindrome (34144922944143).
The spelling of 14112511423002 in words is "fourteen trillion, one hundred twelve billion, five hundred eleven million, four hundred twenty-three thousand, two".
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