14112512051233 has 4 divisors (see below), whose sum is σ = 14149359341568. Its totient is φ = 14075664760900.

The previous prime is 14112512051213. The next prime is 14112512051243. The reversal of 14112512051233 is 33215021521141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14112512051233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14112512051195 and 14112512051204.

It is not an unprimeable number, because it can be changed into a prime (14112512051213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18423644593 + ... + 18423645358.

It is an arithmetic number, because the mean of its divisors is an integer number (3537339835392).

Almost surely, 2^{14112512051233} is an apocalyptic number.

It is an amenable number.

14112512051233 is a deficient number, since it is larger than the sum of its proper divisors (36847290335).

14112512051233 is an equidigital number, since it uses as much as digits as its factorization.

14112512051233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36847290334.

The product of its (nonzero) digits is 7200, while the sum is 31.

Adding to 14112512051233 its reverse (33215021521141), we get a palindrome (47327533572374).

The spelling of 14112512051233 in words is "fourteen trillion, one hundred twelve billion, five hundred twelve million, fifty-one thousand, two hundred thirty-three".