Base | Representation |
---|---|
bin | 1100110101011101010110… |
… | …1110111001111011111111 |
3 | 1211222010222010000121120120 |
4 | 3031113111232321323333 |
5 | 3322210002133112203 |
6 | 50003114553150023 |
7 | 2654412141506655 |
oct | 315272556717377 |
9 | 54863863017516 |
10 | 14112553410303 |
11 | 4551111539747 |
12 | 16bb1356bb313 |
13 | 7b4a67460a0a |
14 | 36b0a0806dd5 |
15 | 197177271b53 |
hex | cd5d5bb9eff |
14112553410303 has 32 divisors (see below), whose sum is σ = 19031972044800. Its totient is φ = 9301157703936.
The previous prime is 14112553410299. The next prime is 14112553410323. The reversal of 14112553410303 is 30301435521141.
It is not a de Polignac number, because 14112553410303 - 22 = 14112553410299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112553410323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 347930938 + ... + 347971496.
It is an arithmetic number, because the mean of its divisors is an integer number (594749126400).
Almost surely, 214112553410303 is an apocalyptic number.
14112553410303 is a deficient number, since it is larger than the sum of its proper divisors (4919418634497).
14112553410303 is a wasteful number, since it uses less digits than its factorization.
14112553410303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43031.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 14112553410303 its reverse (30301435521141), we get a palindrome (44413988931444).
The spelling of 14112553410303 in words is "fourteen trillion, one hundred twelve billion, five hundred fifty-three million, four hundred ten thousand, three hundred three".
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