141131111322433 has 8 divisors (see below), whose sum is σ = 141800838098688. Its totient is φ = 140462778359904.

The previous prime is 141131111322427. The next prime is 141131111322437. The reversal of 141131111322433 is 334223111131141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141131111322433 - 2¹³ = 141131111314241 is a prime.

It is a super-2 number, since 2×141131111322433² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141131111322395 and 141131111322404.

It is not an unprimeable number, because it can be changed into a prime (141131111322437) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 348250441 + ... + 348655462.

It is an arithmetic number, because the mean of its divisors is an integer number (17725104762336).

Almost surely, 2^{141131111322433} is an apocalyptic number.

It is an amenable number.

141131111322433 is a deficient number, since it is larger than the sum of its proper divisors (669726776255).

141131111322433 is an equidigital number, since it uses as much as digits as its factorization.

141131111322433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 696906863.

The product of its digits is 5184, while the sum is 31.

Adding to 141131111322433 its reverse (334223111131141), we get a palindrome (475354222453574).

The spelling of 141131111322433 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred eleven million, three hundred twenty-two thousand, four hundred thirty-three".