141131143113113 has 2 divisors, whose sum is σ = 141131143113114. Its totient is φ = 141131143113112.

The previous prime is 141131143113097. The next prime is 141131143113133. The reversal of 141131143113113 is 311311341131141.

141131143113113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107088492599449 + 34042650513664 = 10348357^2 + 5834608^2 .

It is a cyclic number.

It is not a de Polignac number, because 141131143113113 - 2⁴ = 141131143113097 is a prime.

It is a super-2 number, since 2×141131143113113² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (141131143113133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565571556556 + 70565571556557.

It is an arithmetic number, because the mean of its divisors is an integer number (70565571556557).

Almost surely, 2^{141131143113113} is an apocalyptic number.

It is an amenable number.

141131143113113 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131143113113 is an equidigital number, since it uses as much as digits as its factorization.

141131143113113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1296, while the sum is 29.

Adding to 141131143113113 its reverse (311311341131141), we get a palindrome (452442484244254).

The spelling of 141131143113113 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred forty-three million, one hundred thirteen thousand, one hundred thirteen".