Base | Representation |
---|---|
bin | 100000000101101110110110… |
… | …111110111110000111101011 |
3 | 200111201000210221120211222112 |
4 | 200011232312332332013223 |
5 | 121444244101441334242 |
6 | 1220054511550512535 |
7 | 41504256444352163 |
oct | 4005566676760753 |
9 | 614630727524875 |
10 | 141131400339947 |
11 | 40a72544227406 |
12 | 139b426450574b |
13 | 6099831a1b184 |
14 | 26bcb20b9d5a3 |
15 | 114b2419c6c82 |
hex | 805bb6fbe1eb |
141131400339947 has 2 divisors, whose sum is σ = 141131400339948. Its totient is φ = 141131400339946.
The previous prime is 141131400339901. The next prime is 141131400339961. The reversal of 141131400339947 is 749933004131141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141131400339947 - 228 = 141131131904491 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141131400339895 and 141131400339904.
It is not a weakly prime, because it can be changed into another prime (141131400339977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565700169973 + 70565700169974.
It is an arithmetic number, because the mean of its divisors is an integer number (70565700169974).
Almost surely, 2141131400339947 is an apocalyptic number.
141131400339947 is a deficient number, since it is larger than the sum of its proper divisors (1).
141131400339947 is an equidigital number, since it uses as much as digits as its factorization.
141131400339947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 141131400339947 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred million, three hundred thirty-nine thousand, nine hundred forty-seven".
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